8. (A) A man buys 5kg of meat at Rs.500 per kg. In addition, for every kilogram of meat purchased, he has to pay a consumption tax of 6% on the selling price. Calculate the total amount of money that he has to pay. (B) It takes Ali 30 minutes to mark a paper. Aslam only needs 25 minutes to mark a paper. If they both start marking papers at 10:00 AM, at what time they will finish marking at the same time?

A) Cost of 5kg of meat = 5 x 500 = Rs. 2500 Tax on selling price = 6% of selling price = 6% of 500 = Rs. 30 per kg Total tax on 5kg of meat = 5 x 30 = Rs. 150 Total cost = cost of meat + tax = Rs. 2500 + Rs. 150 = Rs. 2650

Therefore, the man has to pay Rs. 2650.

B) Ali marks a paper in 30 minutes, so he can mark 2 papers in 1 hour. Aslam marks a paper in 25 minutes, so he can mark 2.4 papers in 1 hour.

Let’s find the least common multiple of 30 and 25, which is 150.

Ali will finish marking 5 papers in 150 minutes (2.5 hours). Aslam will finish marking 6 papers in 150 minutes (2.5 hours).

Therefore, they will finish marking at the same time at 12:30 PM.

C) Let’s assume the fare for Rawalpindi to Islamabad is x and the fare for Rawalpindi to Murree is y. Then we can set up the following system of equations:

2x + 3y = 770 3x + 2y = 730

Multiplying the first equation by 2 and the second equation by 3, we get:

4x + 6y = 1540 9x + 6y = 2190

Subtracting the second equation from the first, we get:

5x = 650 x = 130

Substituting x = 130 in either of the two equations, we get:

2(130) + 3y = 770 260 + 3y = 770 3y = 510 y = 170

Therefore, the fare for Islamabad is Rs. 130 and the fare for Murree is Rs. 170.

D) A told B that C is his father’s nephew, which means C is A’s cousin. D is A’s cousin, but not the brother of C, so D and C are first cousins once removed.