A) Cost of 5kg of meat = 5 x 500 = Rs. 2500 Tax on selling price = 6% of selling price = 6% of 500 = Rs. 30 per kg Total tax on 5kg of meat = 5 x 30 = Rs. 150 Total cost = cost of meat + tax = Rs. 2500 + Rs. 150 = Rs. 2650
Therefore, the man has to pay Rs. 2650.
B) Ali marks a paper in 30 minutes, so he can mark 2 papers in 1 hour. Aslam marks a paper in 25 minutes, so he can mark 2.4 papers in 1 hour.
Let’s find the least common multiple of 30 and 25, which is 150.
Ali will finish marking 5 papers in 150 minutes (2.5 hours). Aslam will finish marking 6 papers in 150 minutes (2.5 hours).
Therefore, they will finish marking at the same time at 12:30 PM.
C) Let’s assume the fare for Rawalpindi to Islamabad is x and the fare for Rawalpindi to Murree is y. Then we can set up the following system of equations:
2x + 3y = 770 3x + 2y = 730
Multiplying the first equation by 2 and the second equation by 3, we get:
4x + 6y = 1540 9x + 6y = 2190
Subtracting the second equation from the first, we get:
5x = 650 x = 130
Substituting x = 130 in either of the two equations, we get:
2(130) + 3y = 770 260 + 3y = 770 3y = 510 y = 170
Therefore, the fare for Islamabad is Rs. 130 and the fare for Murree is Rs. 170.
D) A told B that C is his father’s nephew, which means C is A’s cousin. D is A’s cousin, but not the brother of C, so D and C are first cousins once removed.